# Series Completion

Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

5, 2, 7, 9, 16, 25, ?

**Answer**: (a)

Each term in the series, except the first two terms, is the sum of the preceding two

terms.

So, missing term = 16 + 25 = 41.

11, 13, 17, 19, 23, 25, ?

**Answer**: (c)

The pattern is + 2, + 4, + 2, + 4, .....

So, missing term = 25 + 4 = 29.

0, 2, 3, 5, 8, 10, 15, 17, 24, 26, ?

**Answer**: (d)

The given sequence is a combination of two series :

I. 0, 3, 8, 15, 24, ? and II. 2, 5, 10, 17, 26

The pattern in each one of I and II is + 3, + 5, + 7, + 9, .....

So, missing term = 24 + 11 = 35.

0.5, 0.55, 0.65,0.8,?

**Answer**: (c)

The pattern is + 0.05, + 0.10, + 0.15,.....

So, missing term = 0.8 + 0.20 = 1.

1, 2, 6, 7, 21, 22, 66, 67, ?

**Answer**: (c)

The pattern is + 1, x 3, + 1, x 3, + 1, x 3, + 1,.....

So, missing term = 67 x 3 = 201.

2, 8, 16, 128, ?

**Answer**: (c)

Each term in the series, except the first two terms, is the product of the preceding two terms.

So, missing term = 16 x 128 = 2048.

5824, 5242, ?, 4247, 3823

**Answer**: (b)

Each term in the series is obtained by subtracting from the preceding term the number

formed by the first three digits of the preceding term.

So, missing term = 5242 - 524 = 4718.

4832, 5840, 6848, ?

**Answer**: (c)

The pattern is + 1008.

So, missing term - 6848 + 1008 = 7856.

2, 15, 4, 12, 6, 7, ?, ?

**Answer**: (b)

Let the missing terms of the series be x1 and x2.

Thus, the sequence 2, 15, 4, 12, 6, 7, x1 x2 is a combination of two series :

I. 2, 4, 6, x1 and II. 15, 12, 7, x2I consists of consecutive even numbers.

So, missing term, x1 = 8.

The pattern in II is - 3, - 5,......So, missing term, x2 = 7 - 7 = 0.

1, 1, 2, 6, 24, ?, 720

**Answer**: (d)

The pattern is x 1, x 2, x 3, x 4,.....

So, missing term = 24 x 5 = 120.

0

## Attempted

0

## Correct

0