A train 110 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?

Answer: (b)

Speed of train relative to man = (60 + 6) km/hr = 66 km/hr.

\(\left ( 66 \times \frac{5}{18} \right )\) m/sec = \(\frac{55}{3}\) m/sec

∴ Time taken to pass the man = \(\left ( 110 \times \frac{3}{55} \right )\) m/sec = 6 sec.