A train 110 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?

$$\left ( 66 \times \frac{5}{18} \right )$$ m/sec = $$\frac{55}{3}$$ m/sec
∴ Time taken to pass the man = $$\left ( 110 \times \frac{3}{55} \right )$$ m/sec = 6 sec.